RADIATION EXCHANGE MULTIPLE CHOICE QUESTIONS (MCQ) WITH ANSWERS
RADIATION EXCHANGE
MULTIPLE CHOICE QUESTIONS
(MCQ) WITH ANSWERS
MCQ increase knowledge and clarity
about a topic. Shape factors depend upon
the geometry and orientation of the surfaces.
Number of shape factors for n bodies is n2.
Find shape factors from shape factor
algebra and graphs. These help to find the
radiation exchange between two bodies. MCQ
help to apply shape factors in real life applications.
Radiation exchange is controllable. It greatly
depends upon the size, orientation,
medium in between, distance and
emissivity of surfaces.
Fig. Radiant Heat Exchange Between Two Non-black Parallel Infinite Surfaces
Fig. Shape Factors For Aligned Parallel Surfaces
Fig. Shape factors between two rectangular surfaces at right angles
1. Radiation shape factor is also
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Geometrical factor
-
Configuration Or View factor
-
(a) & (b)
-
None
ANS: (c )
-
Shape factor depends upon
-
Firstly Geometry and orientation of emitting surface
-
Secondly Geometry & orientation of collecting surface
-
(a) & (b)
-
None
ANS: (c )
-
Symbol for shape factor for black bodies is
-
Fij
-
fij
-
(a) & (b)
-
None
ANS: (a)
-
Shape factor Fij is
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Firstly Direct radiations from body2 on body 1/Total radiations emitted by body 2
-
Secondly Direct radiations from body1 on body 2/Total radiations emitted by body 1
-
Thirdly Direct radiations from body2 on body 1/Total radiations emitted by body 1
-
None
ANS:(b)
-
Find shape factors from
-
Shape factor algebra
-
Graphs
-
(a) & (b)
-
None
ANS: (c )
-
Use graphs to find shape factors for
-
Parallel surfaces
-
Perpendicular surfaces
-
Parallel & perpendicular surfaces
-
None
ANS: (c )
-
Utility of shape factor is in finding radiation exchange between
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Two surfaces
-
Three surfaces
-
Any number of surfaces
-
None
ANS: (c )
-
Find shape factor easily for
-
Simple shapes
-
Complex shapes
-
Simple & complex shapes
-
None
ANS: (a)
-
How to find shape factor for complex geometries?
-
Directly from the graphs
-
Dividing the complex shape into simple shapes
-
Both (a) & (b)
-
None
ANS: (b)
-
How many shape factors are there between ‘n’ bodies?
-
Firstly n3
-
Secondly n
-
Thirdly n2
-
None
ANS: (c )
-
Shape factor algebra is
-
Sum of shape factors
-
Difference of shape factors
-
Inter-relation between shape factors
-
None
ANS: (c )
-
Find shape factors using
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Law of summation
-
Law of reciprocity & la of energy conservation
-
From (a ) & (b)
-
None
ANS: (c )
-
Law of summation between two surfaces is
-
Firstly F11+F12+F22+ F21 =0
-
Secondly F11+F12+F22+ F21 =1
-
Both (a) & (b)
-
None
ANS: (d)
-
Law of summation between body 1 and body 2 is
-
Firstly F11+F12 =1
-
Secondly F21+F22=1
-
Both (a) & (b)
-
None
ANS: (c )
-
Law of reciprocity between body 1 and 2 is
-
Firstly A1F11=A2 F22
-
Secondly A1F12=A2 F22
-
Thirdly A1F11=A2 F21
-
None
ANS: (d)
-
Law of summation is applicable for
-
Two bodies
-
Three bodies
-
n bodies
-
None
ANS: (c )
-
Law of reciprocity is applicable between
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Two bodies
-
Three bodies
-
n bodies
-
None
ANS: (a)
-
Shape factors F11, F22, F33—for flat bodies is
-
Zero
-
1
-
2
-
None
ANS: (a)
-
Shape factor for a convex surface is
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Zero
-
1
-
2
-
None
ANS: (a)
-
Shape factor for a concave surface is
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Zero
-
Non zero
-
3
-
None
ANS: (b)
-
Shape factor between two grey bodies is
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F12
-
f12
-
Both (a) & (b)
-
None
ANS: (b)
-
Interchange factor f12 for two infinite parallel surfaces is given as
-
Firstly 1/(1/€1+1/€2)
-
Secondly 1/(1/€1+1/€2 -1)
-
Thirdly 1/(1/€1+1/€2 + 1)
-
None
ANS: (b)
-
Shape factor between two long concentric cylinders is
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Firstly 1/(1/€1+1/€2)
-
Secondly 1/[(1/€1+(A2/A1)(1/€2)]
-
Thirdly 1/[(1/€1+(A1/A2(1/€2 -1)]
-
None
ANS: (c)
-
Shape factor between two small grey bodies is
-
Firstly 1/(1/€1+1/€2)
-
Secondly 1/€1€2
-
Thirdly €1€2
-
None
ANS: (c )
-
Shape factor for body 1 completely enclosed by body 2, body 1 is small
-
1/€1€2
-
€1€2
-
€1
-
None
ANS: (c )
-
Shape factor for body 1 completely enclosed by body 2, body 1 is large size
-
1/€1€2
-
€1€2
-
€1
-
None
ANS: (d )
-
Shape factor for body 1 completely enclosed by body 2, body 1 is small
-
Firstly 1/(1/€1+1/€2)
-
Secondly 1/[(1/€1+(A2/A1)(1/€2)]
-
Thirdly 1/[(1/€1+(A1/A2(1/€2 -1)]
-
None
ANS: (c )
28. One of the methods used to find the shape factor is
(a) Law of difference
(b) Law of summation
(c) Law of multiplication
(d) None
ANS: (b)
29. Number of shape factors for 3 bodies is
-
-
(a) 3 x 1
-
(b) 3 x 2
-
(c) 3 x 3
-
(d) None
-
ANS: ©
30. Law of summation for 3 bodies is
(a) F12+F21+F13=1
(b) F33+F31+F13=1
(c) F11+F21+F13=1
(d) None
ANS: (d)
31. Law of Reciprocity states
(a) A1 F12 = A2 F22
(b) A1F12 = A2 F21
(c) F11+F12 =1
(d) None
ANS: (b)
31. Value of the shape factor F12 for a small body 1 enclosed in a big body 2 is
(a) < 1
(b) >1
(c) =1
(d) None
ANS: ©
32. Radiation between non-black surfaces depends upon
-
Radiative properties & temperatures
-
Geometry and orientations
-
Both (a) & (b)
-
None
ANS: (c )
33. Radiation exchange between black surfaces depends upon
-
Radiative properties & temperatures
-
Temperatures & shape factors
-
Both (a) & (b)
-
None
ANS: (b)
34. Radiation exchange between two black surfaces 1 and 2 given as
(a) A1F21σb (T14-T24) OR A2F12σb (T14-T24)
(b) A1F12σb (T14-T24) OR A2F21σb (T14-T24)
(c) A1F21σb (T14-T24) + A1F12σb (T14-T24)
(d) None
ANS: (b)
35. Assumption used in radiation exchange between surfaces is
-
Surfaces separated by participating mediums
-
Surfaces separated by non-participating medium
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Both (a) & (b)
-
None
ANS: (b)
36. A non-participating medium which do not
-
Emits
-
Absorbs
-
Emits & absorbs
-
None
ANS: (c )
37. Practical example of non-participating medium is
-
Water vapors
-
Carbon dioxide
-
Other gases
-
None
ANS: (c )
38.Practical example of participating medium is
-
Water vapors
-
Carbon dioxide
-
Both water vapors & carbon dioxide
-
None
ANS: (c )
39. Radiation exchange is studied with
-
Electrical network approach
-
Radiation shields
-
Both (a) & (b)
-
None
ANS: ©
40. Radiation exchange between two black bodies is
-
Complex
-
Simple
-
Both simple & complex
-
None
ANS: (b)
41. Electrical network approach requires
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Radiosity
-
Irradiation
-
Both radiosity & irradiation
-
None
ANS: (c )
42. Non-black bodies for radiation exchange are
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Transparent
-
Opaque
-
Both opaque & transparent
-
None
ANS: (b)
43. Radiosity is
-
Firstly Sum of transmitted and emitted radiations/m2s
-
Secondly Sum of transmitted & reflected radiations/m2s
-
Thirdly Sum of emitted & reflected radiations/m2s
-
None
ANS: (c )
44. Irradiation is
-
Firstly Total reflected radiant energy/m2s
-
Secondly Total radiant incident radiations/m2s
-
Thirdly Total reflected & incident radiations/m2s
-
None
ANS: b)
45. The symbol for radiosity is
-
G
-
J
-
E
-
None
ANS: (b)
46. The symbol for irradiation is
-
G
-
J
-
E
-
None
ANS: (a)
Fig. Surface and Space Resistances between two radiating Surfaces
Fig. Surface & Space Resistances Between Three Bodies Not in a line
47. Surface resistance for a non-black body is
-
(1-€)/€
-
€/(1-€)
-
(1-€)/€A
-
None
ANS: (c )
48. Space resistance is
-
Firstly 1/A1F11
-
Secondly 1/A1F12
-
Thirdly 1/A2F12
-
None
ANS: (b)
49. How many surface and space resistances between two non-black bodies?
-
1,3
-
2,2
-
2,4
-
None
ANS: (b)
50. How many surface resistances and space resistances between two black bodies?
-
Firstly 0, 3
-
Secondly 0, 4
-
Thirdly 0,2
-
None
ANS: (c )
51. To reduce radiation exchange between two bodies, use a
-
Radiosity
-
Radiation shield
-
Irradiation
-
None
ANS: (b)
52. Radiation shield is a
-
Transparent body
-
Opaque body
-
Black body
-
None
ANS: (b)
53. A radiation shield has
-
High absorptivity & high reflectivity
-
High transmissivity & high reflectivity
-
Low absorptivity & high reflectivity
-
None
ANS: (c )
54. Preferable radiation shield is thin sheet of
-
Copper or aluminum
-
Steel or cast iron
-
Paper or board
-
None
ANS: (a)
55. Radiation exchange between two infinite parallel non-black bodies is
-
Firstly Q12=Aσb(T14—T24)/(1/€1)
-
Secondly Q12=Aσb(T14—T24)/(1/€1 +1/€2 +1)
-
Thirdly Q12=Aσb(T14—T24)/(1/€1+ 1/€2–1)
-
None
ANS: (c )
56. Radiation exchange between two non-black parallel infinite surfaces & radiation shield of same emissivity is as compared to without radiation shield is
-
1/3
-
¼
-
1/6
-
None
ANS: (d)
57. Radiation exchange between two non-black parallel infinite surfaces & radiation shield of same emissivity is as compared to without radiation shield is
-
1/2
-
1/3
-
1/4
-
None
ANS: (a)
58. With €1=€2=€ shield, the temperature of the radiation shield is
-
T14 +T24
-
(1/3)( T14 +T24)
-
(1/2)( T14 +T24)
-
None
ANS: (c )
59. With n shields in between two non-black parallel surfaces with same emissivity, €1=€2=€ shields, the radiation exchange is
(a) (1/n) [A σb (T14 –T24)/((2/€)–1))]
(b) (1/(n+1)) [A σb (T14 –T24)/((2/€)–1))]
© (1/(n-1)) [A σb (T14 –T24)/((2/€)–1))]
(d) None
ANS: (b)
60. How many space resistances with n shields in between two non-black parallel radiating surfaces?
-
n
-
n-1
-
n+1
-
None
ANS: (c)
61. How many surface resistances with n shields in between two non-black parallel radiating surfaces?
-
n+2
-
n-2
-
n+1
-
None
ANS: (a)
62. . The expression for radiosity is
-
(a) ρα + ϵ Eb
-
(b) ρα — ϵ Eb
-
(c) ρG+ ϵEb
-
(d) None
ANS: ©
63. Radiosity equals emissive power for a
(a) Grey body
(b) White body
(c) Red body
(d) None
ANS: (d)
64. Number of Radiation shields of same emissivity reducing radiation exchange by one half.
(a) 1
(b) 2
(c) 3
(d) None
ANS: (a)
65. Radiosity ‘J’ for a black body is equal to the
(a) ρG+ ϵEb
(b) Eb
(c) ϵEb
(d) None
ANS: (b)
66. Radiation exchange between two grey bodies is given by
(a) (Eg1 – Eg2)/[(1-ϵ1)/ϵ1 A1) + 1/A1 F12 + (1-ϵ2)/ϵ2 A2)]
(b) (Eb1 – Eb2)/[(1-ϵ1)/ϵ1 A1) + 1/A1 F12 + (1-ϵ2)/ϵ2 A2)]
(c) (Eg1 – Eg2)/[(1/ϵ1 + + 1/ϵ2 –1]
(d) None
ANS: (b)
67. Surface resistance for a black body is
(a) Twice of a same size grey body
(b) Same as for a same size grey body
(c) Zero
(d) None
ANS: (c)
68. Space resistance depends on
(a) Distance between the two bodies
(b) Size & Orientation of the two bodies with respect to each other
(c) (a) & (b)
(d) None
ANS: (c )
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