CARNOT CYCLE MULTIPLE CHOICE QUESTIONS (MCQ) WITH ANSWERS
CARNOT CYCLE MULTIPLE
CHOICE QUESTIONS
(MCQ) WITH ANSWERS
MCQ help in better understanding.
Carnot Cycle is a most efficient power
producing cycle. It has two isentropic and
two isothermal processes. In the Carnot
Cycle, equations are there for the change
of entropy in a process. Every process in
nature is irreversible. Entropy increases
due to irreversibility. Increase of entropy is
undesirable as it reduces availability.
-
Entropy of a refrigerant is zero in S.I. units at a temperature of
-
00C
-
-400C
-
+1000C
-
None
Ans: (ii)
-
Change of entropy during heating at constant pressure is equal to
-
Cvln(T2/T1)
-
(1+Cp) ln(V2/V1)
-
Cpln(T2/T1)+ Cpln(V2/V1)
-
None
Ans: (i)
-
Under iso-thermal conditions, change of entropy from p1 to p2 will be
-
Firstly Cp ln(p2/p1)
-
Secondly Cv ln(V2/V1)
-
Thirdly Cpln(p2/p1) + Cpln(V2/V1)
-
None
Ans: (i)
-
When is the change of entropy is zero under an
-
Constant temperature process
-
Iso – choric process
-
Constant pressure process
-
None
Ans: (iv)
-
No change of entropy during a
-
Adiabatic process
-
Constant enthalpy process
-
Constant internal energy process
-
None
Ans: (iv)
-
During heating at constant volume process, change of specific entropy is
-
Cv ln (p2/p1)
-
Cp ln (p2/p1)
-
Cp ln (T2/T1)
-
None
Ans: (iv)
-
In an iso-thermal process, change of entropy will be
-
Cp ln (v2/v1)
-
Cv ln (v2/v1)
-
R ln (v2/v1)
-
None
Ans: (iii )
-
General expression for the change of entropy is
-
R ln (v2/v1) + Cp ln(T2/T1)
-
R ln (v2/v1) + Cv ln(T2/T1)
-
Cp ln (v2/v1) + Cp ln(T2/T1)
-
None
Ans: (ii)
-
An adiabatic process will have change of entropy as
-
((n—γ)/(n—1)) ln(T2/T1)
-
Cp ((n—γ)/(n—1)) ln(T2/T1)
-
Cv ((n—γ)/(n—1)) ln(T2/T1)
-
None
Ans: (iii)
-
Reversible adiabatic process will have change of entropy as
-
Cv ((n—γ)/(n—1)) ln(T2/T1)
-
Cp ((n—γ)/(n—1)) ln(T2/T1)
-
((n—γ)/(n—1)) ln(T2/T1)
-
None
Ans: (iv)
-
During an irreversible process, there is
-
Increase of entropy
-
Decrease of entropy
-
No change in entropy
-
None
Ans: (i)
-
Increase of entropy is
-
Good
-
Neither good nor bad
-
Bad
-
None
Ans: (iii)
-
Decrease of entropy is in case of
-
Pressure decrease
-
Decrease in volume
-
Both decrease in pressure & volume
-
None
Ans: (ii)
-
Entropy increases with the
-
Addition of heat
-
Removal of heat
-
At constant heat
-
None
Ans:(i)
-
Under what conditions, entropy becomes double when
-
Temperature is doubled
-
Pressure becomes double
-
Volume is doubled
-
None
Ans: (iv)
-
A Carnot cycle is a
-
real cycle
-
Ideal cycle
-
Experimentally verified cycle
-
None
Ans: (b)
-
On a temperature entropy chart, Carnot cycle will be a
-
Rhombus
-
Rectangle
-
Triangle
-
None
Ans: (ii)
-
The order of processes in a Carnot Cycle is
-
Isothermal—isothermal—isentropic—isentropic
-
isentropic—isothermal–—isothermal-isentropic
-
Isothermal—isentropic——isothermal –isentropic
-
None
Ans: (c)
-
Over the complete Carnot Cycle, entropy
-
increases
-
Decreases
-
No change
-
None
Ans:(iii)
-
With the rise of temperature in a system, sum of entropy of a system and its surroundings
-
Increases
-
Decreases
-
Remains constant
-
None
Ans: (iii)
-
While there is rise of pressure in a system, sum of entropy of a system and its surroundings
-
Increases
-
Decreases
-
Remains constant
-
None
Ans: (iii)
-
A petrol engine assumed to work on Carnot Cycle. It works between temperatures of 12000C and 2000 .The efficiency of the engine will be
-
99 %
-
79 %
-
69 %
-
None
Ans: (iii)
-
Work done will be maximum using pvn=Constant when the value of index ‘n’ will be
-
1
-
4
-
3
-
None
Ans: (ii)
-
Minimum Work will be done using pvn=Constant when the value of index ‘n’ will be
-
1
-
4
-
3
-
None
Ans: (i)
-
Compression ratio in a diesel cycle/petrol cycle is approximately equal to
-
25
-
5
-
15
-
None
Ans: (ii)
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